The typical outer diameter of a 288-fiber loose tube optical cable is approximately 1.7 centimeters (17 mm).

For a 288-fiber multi loose tube cable, the design usually consists of 12 loose tubes, each containing 24 fibers, with individual tube diameters around 2.5–2.8 mm . The central strength member and protective layers, including water-blocking yarn and outer sheath, contribute to the overall cable diameter. According to datasheets, the cable outer diameter (OD) is listed as 17 mm, which converts to 1.7 cm .

Cable Construction Details

• Loose Tubes: 12 tubes × 24 fibers per tube, each tube ~2.5–2.8 mm in diameter .
• Central Strength Member: Provides tensile strength and prevents bending damage.
• Sheath Material: Typically UV-stable, halogen-free, flame-retardant (HFFR) for outdoor and indoor use.
• Waterblocking: Jelly-filled tubes or water-blocking yarn prevent moisture ingress.

Practical Considerations

• The outer diameter affects duct and conduit sizing, installation flexibility, and bending radius.
• High fiber density cables like the 288-fiber type are designed to maximize capacity while minimizing space, making them suitable for backbone networks, campus backbones, and industrial applications . In summary, a standard 288-fiber loose tube optical cable has an outer diameter of about 1.7 cm, with individual tube diameters of 2.5–2.8 mm, and includes protective layers and a central strength member to ensure durability and ease of installation.